who could come up with this

[cisco]

This is pretty cool!

1. Grab a calculator (you won't be able to do this one in your head).
2. Key in the first three digits of your phone number (NOT the area
code).
3. Multiply by 80.
4. Add 1.
5. Multiply by 250.
6. Add the last 4 digits of your phone number.
7. Add the last 4 digits of your phone number again.
8. Subtract 250.
9. Divide number by 2.

Recognize the answer?

 

[buddy]

lmao!!!

 

[freelancc]

:look:

 

[CryBoy]

Who could come up with this?

Someone with too much time on his side.

 

[yyz]

When I dail the number, I get a busy signal..........strange.

 

[Chopsticks]

Maw????

 

[Captain Crunch]

I dialed the number and got BeantownJim. WTF How does that work.:shrug: :shrug:

 

[Chopsticks]

just to spoil your math magic...LOL

just to spoil your math magic...LOL

xxx*80
a.. This will ALWAYS yield a 5-digit number ending in zero.
+1
a.. One of the "tricks" and is needed for the next step. It leaves
your
5-digit number intact but now the least significant digit is 1.
*250
a.. The confusion factor. The function here is to shift everything
to the
left a couple of places. Because of the previous step ending in "1" it
will
always yield a number with the last four digits of "0250"
+zzzz
+zzzz
a.. Oh boy, more confusion. Even worse, it's added twice. But
notice
that adding twice is the same as multiplying the last 4 digits of your
phone
number by 2, and then adding it.
-250
a.. Now for the slight-of-hand maneuver. This functions to eliminate
that
cumbersome "0250" that was inserted earlier.
/2

 

[yyz]

Now I get it!

:shrug:

 

[jmizeus]

i dont know, seems cool but i have done this 7 times and come up w/the wrong answer/number:shrug:

 

[VaNurse]

Chopsticks, is this what you meant?

Step 1) done
Step 2) X is your 3-digit number
Step 3) 80X
Step 4) 80X+1
Step 5) 80X+1(250) or 20000X+250
Step 6) 20000X+250+Y (Y is your 4-digit number)
Step 7) 20000X+250+Y+Y or 20000X+250+2Y
Step 8) 20000X+250+2Y-250 or 20000X+2Y
Step 9) 20000X+2Y divided by 2 or 10000X+Y

It HAS been 30 years since Algebra for me so I could be wrong!

 

[KMA]

Does this help???

1. Take the first three digits of your phone number (not area code).
Let x be the first three digits
2. Multiply by 80.
80 x
3. Add 1.
80 x + 1
4. Multiply by 250.
250 ( 80 x + 1)
5. Add the last four digits of your phone number.
Let y be the last four digits
250 ( 80 x + 1) + y
6. Add the last four digits of your phone number again.
250 ( 80 x + 1) + 2 y
7. Subtract 250.
250 ( 80 x + 1) + 2 y - 250
8. Divide by 2.
[ 250 ( 80 x + 1) + 2 y - 250 ] / 2
= [ 20000 x + 250 + 2 y - 250 ] / 2

= [ 20000 x + 2 y ] / 2

= 10000 x + y

= phone number

 

[jmizeus]

sorry mine still comes up wrong? my 1st 3 are right..but last 4 are wrong..i have a 0836 last 4 and it comes up 0017?

 

[jmizeus]

neevr mind..i was adding all 4 numbers together..not all at once..neat