Have been playing blackjack on several gambling (12 trips in fact 9 winners 3 losers) basic strat. no counting level bets .......up approx 5o units total in approx 250 hours realize this is against the curve should be negative............what are the odds of this ?? or how do i calculate........have been comped well......but know unless counting in long run will lose back any help appreciated .......
blackjack help needed probability ?
- Thread starter doubleon11
- Start date
thanks for the link and good luck in Vegas
thanks for the link and good luck in Vegas
do you go to Atlantic City or Foxwoods any?? curious how conditions are there to play BJ notice you are from the NE
thanks for the link and good luck in Vegas
do you go to Atlantic City or Foxwoods any?? curious how conditions are there to play BJ notice you are from the NE
I haven't made it to AC or the tribal casinos in Connecticut- I play the casinos in Arizona and Vegas a few times a year but just recreationally- i.e. too boozed up to count
2B
---
11
If you have access to a multiple-precision math software package like Mathematica, then I can tell you how to figure it out - or at least get a close approximation. The numbers are too big to work out on a standard graphing calculator that I have here.
Assuming you are playing 45 hands an hour, then in 250 hours you are playing 11,250 hands. For a +50 profit, you are winning 5650 and losing 5600. Probability of winning a hand is approx .49 and losing .51. If these numbers arent accurate enough to just use the below formula with your own probabilities.
You have to compute the probability of getting at least 5650 wins in 11,250 hands.
Sum across "i" => ["11250 choose i"] x [.49^i] x [.51^(11250-i)]
The sum runs from i = 5650 to 11250.
It wont be exact but it will be close. I am not factoring in doubling, surrendering, or any other kinds of strategies. Just basic win/lose.
---
11
If you have access to a multiple-precision math software package like Mathematica, then I can tell you how to figure it out - or at least get a close approximation. The numbers are too big to work out on a standard graphing calculator that I have here.
Assuming you are playing 45 hands an hour, then in 250 hours you are playing 11,250 hands. For a +50 profit, you are winning 5650 and losing 5600. Probability of winning a hand is approx .49 and losing .51. If these numbers arent accurate enough to just use the below formula with your own probabilities.
You have to compute the probability of getting at least 5650 wins in 11,250 hands.
Sum across "i" => ["11250 choose i"] x [.49^i] x [.51^(11250-i)]
The sum runs from i = 5650 to 11250.
It wont be exact but it will be close. I am not factoring in doubling, surrendering, or any other kinds of strategies. Just basic win/lose.
