Math Wizards....front and center!

[buddy]

Why does the function f (x) = x^6 +1 not have any x - intercepts?

 

[KotysDad]

It doesnt have any "real" solutions, but there are 6 imaginary ones.

For a real x-int, you have to solve

0 = x^6 + 1
-1 = x^6

For any real x, x^6 is a positive number.

 

[ppabart]

right...since x^6 + 1 will always be a positive number, it can't intercept the x-axis

 

[buddy]

Thank you!

 

[1%er]

 

[the addict]

Why does the function f (x) = x^6 +1 not have any x - intercepts?

is that spanish?:shrug:

 

[The Joker]

 

[Nole]

Why does the function f (x) = x^6 +1 not have any x - intercepts?

No Favre?



:shrug: