Okay, here it goes. Let me know if any of this doesn't make sense, I may confuse myself writing this up
Okay, so this is all figured out on base 2 math.
Let's look at the pearls in that friggen genie's hands as the game starts. "p" stands for a single pearl.
p p p
p p p p
p p p p p
p p p p p p
In base 2 math,
1= 0 0 1
2= 0 1 0
3= 0 1 1 (the combo of 1 and 2 above)
4= 1 0 0
5= 1 0 1 (the combo of 1 and 4 above)
6= 1 1 0 (the combo of 2 and 4 above)
If you are lost at this point, sorry, it's a bit confusing. So in the genies hands, these are the pearls:
p p p there are 3, so that equals 0 1 1 from above
p p p p there are 4, wo that equals 1 0 0
p p p p p there are 5 so that equals 1 0 1
p p p p p p there are 6 so that equals 1 1 0
Rewriting the genies hand in this new code, it is:
0 1 1 (3 pearls)
1 0 0 (4 pearls)
1 0 1 (5 pearls)
1 1 0 which adds up to (add downwards) :
3 2 2
Now, here's the key. You never want any odd numbers after you convert the genie's pearls. So, in the start of the game, you'd take all but 2 away from the last row. That way you will have:
0 1 1
1 0 0
1 0 1
0 1 0 which add to:
2 2 2
See how i got rid of the odd number. Now when the genie takes one/some away, he will create odds again. You must make all evens every time, you will win every time.
Phew....that may be a foreign language to some. If it doesn't make sense maybe I can apply it to a sample game i'll play. Just remember you have to use a pen and write out the "code" every time the hand changes.
Good luck
