Let this sink in.........

The Joker

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homedog

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What is the force of the buckets exerted onto the table top? :0corn
 

MadJack

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What is the force of the buckets exerted onto the table top? :0corn
For 4 buckets, the total weight of one bucket and rope needs to be at least a little bit over 25% the total weight of the table and rope. All 4 buckets total is 100% the weight of the table, plus a bit. The buckets overcome the weight of the table (and rope), go down and lift the table and eventually come to a stop on the surface of the table itself. Elementary, my dear mavaction!
If:
N = total # of buckets
N[SUP]m[/SUP] = total mass of buckets
n = 1/N
n[SUP]m[/SUP] = n * N[SUP]m[/SUP]
T = total mass of table
t = n * T
r[SUP]a[/SUP] = mass of rope on bucket side of pulley
r[SUP]b[/SUP] = mass of rope on table side pulley
R[SUP]a[/SUP] = total mass of rope on bucket side of pulley
R[SUP]b[/SUP] = total mass of rope on table side of pulley
Q = Unknown additional mass constant to overcome equilibrium and friction coefficient of the pulley and the rope. See "little bit" above. (lol?)
q = n * Q
S[SUP]a[/SUP] = total mass of bucket side of pulley
S[SUP]b[/SUP] = total mass of table side of pulley

then to see results like in the picture:
S[SUP]a[/SUP] = N[SUP]m[/SUP] + Q + R[SUP]a[/SUP]
S[SUP]b[/SUP] = T + R[SUP]b[/SUP]
S[SUP]a[/SUP] > S[SUP]b[/SUP]
n[SUP]m[/SUP] + q + r[SUP]a[/SUP] > t + r[SUP]b[/SUP]
N[SUP]m[/SUP] + Q + R[SUP]a[/SUP] > T + R[SUP]b[/SUP]
Q > T + R[SUP]b[/SUP] - R[SUP]a[/SUP] - N[SUP]m

[/SUP]:0008
 

Full court press

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For 4 buckets, the total weight of one bucket and rope needs to be at least a little bit over 25% the total weight of the table and rope. All 4 buckets total is 100% the weight of the table, plus a bit. The buckets overcome the weight of the table (and rope), go down and lift the table and eventually come to a stop on the surface of the table itself. Elementary, my dear mavaction!
If:
N = total # of buckets
N[SUP]m[/SUP] = total mass of buckets
n = 1/N
n[SUP]m[/SUP] = n * N[SUP]m[/SUP]
T = total mass of table
t = n * T
r[SUP]a[/SUP] = mass of rope on bucket side of pulley
r[SUP]b[/SUP] = mass of rope on table side pulley
R[SUP]a[/SUP] = total mass of rope on bucket side of pulley
R[SUP]b[/SUP] = total mass of rope on table side of pulley
Q = Unknown additional mass constant to overcome equilibrium and friction coefficient of the pulley and the rope. See "little bit" above. (lol?)
q = n * Q
S[SUP]a[/SUP] = total mass of bucket side of pulley
S[SUP]b[/SUP] = total mass of table side of pulley

then to see results like in the picture:
S[SUP]a[/SUP] = N[SUP]m[/SUP] + Q + R[SUP]a[/SUP]
S[SUP]b[/SUP] = T + R[SUP]b[/SUP]
S[SUP]a[/SUP] > S[SUP]b[/SUP]
n[SUP]m[/SUP] + q + r[SUP]a[/SUP] > t + r[SUP]b[/SUP]
N[SUP]m[/SUP] + Q + R[SUP]a[/SUP] > T + R[SUP]b[/SUP]
Q > T + R[SUP]b[/SUP] - R[SUP]a[/SUP] - N[SUP]m

[/SUP]:0008


I didn't get it at first but after reading Jacks explanation it is so simple. God, I'm such a dope sometimes :facepalm:
 

fatdaddycool

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Mar 26, 2001
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Fort Worth TX usa
For 4 buckets, the total weight of one bucket and rope needs to be at least a little bit over 25% the total weight of the table and rope. All 4 buckets total is 100% the weight of the table, plus a bit. The buckets overcome the weight of the table (and rope), go down and lift the table and eventually come to a stop on the surface of the table itself. Elementary, my dear mavaction!
If:
N = total # of buckets
N[SUP]m[/SUP] = total mass of buckets
n = 1/N
n[SUP]m[/SUP] = n * N[SUP]m[/SUP]
T = total mass of table
t = n * T
r[SUP]a[/SUP] = mass of rope on bucket side of pulley
r[SUP]b[/SUP] = mass of rope on table side pulley
R[SUP]a[/SUP] = total mass of rope on bucket side of pulley
R[SUP]b[/SUP] = total mass of rope on table side of pulley
Q = Unknown additional mass constant to overcome equilibrium and friction coefficient of the pulley and the rope. See "little bit" above. (lol?)
q = n * Q
S[SUP]a[/SUP] = total mass of bucket side of pulley
S[SUP]b[/SUP] = total mass of table side of pulley

then to see results like in the picture:
S[SUP]a[/SUP] = N[SUP]m[/SUP] + Q + R[SUP]a[/SUP]
S[SUP]b[/SUP] = T + R[SUP]b[/SUP]
S[SUP]a[/SUP] > S[SUP]b[/SUP]
n[SUP]m[/SUP] + q + r[SUP]a[/SUP] > t + r[SUP]b[/SUP]
N[SUP]m[/SUP] + Q + R[SUP]a[/SUP] > T + R[SUP]b[/SUP]
Q > T + R[SUP]b[/SUP] - R[SUP]a[/SUP] - N[SUP]m

[/SUP]:0008

Oh! Is the movie over already?
 

Cricket

sporadic wins
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Picture is upsidedown, buckets are glued to table.Strings are actually white curtain rods! :lol2: ::dizzy:
 
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